Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Doppler Effect›Question 59

NEET 2017 · Doppler Effect

Doppler Effect question from NEET 2017

Q59NEET 2017Easy

Doppler Effect

Two cars moving in opposite directions approach each other with speed of 22 ms−1{}^{-1} and 16.5 m s−1{}^{-1} respectively. The driver of the first car blows a horn having a frequency 400 Hz. The frequency heard by the driver of the second car is (velocity of sound is 340 m s−1{}^{-1})

Show answer and solution

Answer: (c)

  1. Both approaching: n′=nv+vov−vsn' = n\frac{v + v_o}{v - v_s}, with vs=22v_s = 22 m/s, vo=16.5v_o = 16.5 m/s.
  2. n′=400×340+16.5340−22=400×356.5318n' = 400 \times \frac{340 + 16.5}{340 - 22} = 400 \times \frac{356.5}{318}
  3. n′≈448n' \approx 448 Hz. So the answer is (c) 448 Hz.
Report a mistake

More questions on Doppler Effect