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NEET 2016 (Phase 2) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from NEET 2016 (Phase 2)

Q32NEET 2016 · PHASE 2Easy

Velocity, Acceleration & Variable Motion

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by

xP(t) = (at + bt2) and xQ(t) = (ft $-$ t2).

At what time do the cars have the same velocity?

Show answer and solution

Answer: (d)

$v_P = a + 2bt$ , $v_Q = f - 2t$ .
$a + 2bt = f - 2t \Rightarrow 2t(1 + b) = f - a$
So the answer is (d) $t = \frac{f - a}{2(1 + b)}$ .

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