Two cells are connected in opposition as shown. Cell E₁ is of 8 V emf and 2 Ω internal resistance; the cell E₂ is of 2 V emf and 4 Ω internal resistance. The terminal potential difference of cell E₂ is __________ V. Numerical answer type. Work it out, then open the answer.

Answer: 6. Cells in opposition, no external resistor: I = (E₁ - E₂)/(r₁ + r₂) = (8 - 2)/(2 + 4) = 1 A. Current enters E₂ at its positive terminal, so E₂ is being charged. V₂ = E₂ + Ir₂ = 2 + 1 × 4 Terminal p.d. of E₂ = 6 V

Two cells are connected in opposition as shown. Cell E₁ is of 8 V emf… | JEE Main 2024 (30 Jan, Shift 1)

Q12JEE Main 2024 · 30 JAN · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

Two cells are connected in opposition as shown. Cell $E_1$ is of $8\text{ V}$ emf and $2\ \Omega$ internal resistance; the cell $E_2$ is of $2\text{ V}$ emf and $4\ \Omega$ internal resistance. The terminal potential difference of cell $E_2$ is __________ V.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

Cells in opposition, no external resistor: $I = \dfrac{E_1 - E_2}{r_1 + r_2} = \dfrac{8 - 2}{2 + 4} = 1\text{ A}$ .
Current enters $E_2$ at its positive terminal, so $E_2$ is being charged.
$V_2 = E_2 + Ir_2 = 2 + 1 \times 4$
Terminal p.d. of $E_2$ $= 6\text{ V}$

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