Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Cells: EMF, Internal Resistance & Combinations›Question 47

NEET 2006 (AIPMT) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from NEET 2006 (AIPMT)

Q47NEET 2006 · AIPMTMedium

Cells: EMF, Internal Resistance & Combinations

Two cells, having the same e.m.f. are connected in series through an external resistance R. Cells have internal resistances r1 and r2 (r1 > r2) respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of R is

Show answer and solution

Answer: (b)

  1. I=2ER+r1+r2I = \frac{2E}{R + r_1 + r_2}
  2. P.d. across first cell zero: E=Ir1⇒2Er1R+r1+r2=EE = Ir_1 \Rightarrow \frac{2E r_1}{R + r_1 + r_2} = E
  3. R+r1+r2=2r1⇒R=r1−r2R + r_1 + r_2 = 2r_1 \Rightarrow R = r_1 - r_2. So the answer is (b).
Report a mistake

More questions on Cells: EMF, Internal Resistance & Combinations