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JEE Main 2022 (25 Jun, Shift 2) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2022 (25 Jun, Shift 2)

Q22JEE Main 2022 · 25 JUN · SHIFT 2Medium

Cells: EMF, Internal Resistance & Combinations

Two cells of same emf but different internal resistances r1 and r2 are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, is:

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Answer: (a)

  1. Series cells: I=2ER+r1+r2I = \dfrac{2E}{R + r_1 + r_2}.
  2. Terminal p.d. of second cell is zero: E−Ir2=0⇒I=Er2E - Ir_2 = 0 \Rightarrow I = \dfrac{E}{r_2}.
  3. 2ER+r1+r2=Er2⇒2r2=R+r1+r2\dfrac{2E}{R + r_1 + r_2} = \dfrac{E}{r_2} \Rightarrow 2r_2 = R + r_1 + r_2
  4. So the answer is (a) R=r2−r1R = r_2 - r_1.
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