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JEE Main 2026 (2 Apr, Shift 1) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2026 (2 Apr, Shift 1)

Q18JEE Main 2026 · 2 APR · SHIFT 1Medium

Electric Potential & Equipotentials

Two charged conducting spheres $S_1$ and $S_2$ of radii 8 cm and 18 cm are connected to each other by a wire. After equilibrium is established, the ratio of electric fields on $S_1$ and $S_2$ spheres are $E_{S1}$ and $E_{S2}$ respectively. The value of $\frac{E_{S1}}{E_{S2}}$ is ________.

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Answer: (d)

Connected spheres: $\frac{kq_1}{r_1} = \frac{kq_2}{r_2}$ , and $E = \frac{kq}{r^2} = \frac{V}{r} \propto \frac{1}{r}$ .
$\frac{E_{S1}}{E_{S2}} = \frac{r_2}{r_1} = \frac{18}{8} = \frac{9}{4}$
So the answer is (d) $\frac{9}{4}$ .

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