Two charged particles each having a charge ' +q ' and mass 'm' are… | MHT CET 2026 (19 May, Shift 1)

Q15MHT CET 2026 · 19 MAY · SHIFT 1Medium

Electric Charge & Coulomb's Law

Two charged particles each having a charge ' $+q$ ' and mass 'm' are kept at a distance 'd'. If they are in equilibrium under the gravitational force and the electric force between them, then the ratio $\frac{q}{m}$ (specific charge) of each particle is ( $G$ - Universal gravitation constant, $\varepsilon_0$ = permittivity of free space)

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Answer: (c)

Equilibrium: electric repulsion = gravitational attraction.
$\dfrac{1}{4\pi\varepsilon_0}\dfrac{q^2}{d^2} = \dfrac{Gm^2}{d^2} \Rightarrow \dfrac{q^2}{m^2} = 4\pi\varepsilon_0 G$
So the answer is (c) $\dfrac{q}{m} = \sqrt{4\pi\varepsilon_0 G}$ .

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