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JEE Main 2024 (29 Jan, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2024 (29 Jan, Shift 1)

Q46JEE Main 2024 · 29 JAN · SHIFT 1Easy

Electric Flux & Gauss's Law

Two charges of 5Q5Q and −2Q-2Q are situated at the points (3a,0)(3a, 0) and (−5a,0)(-5a, 0) respectively. The electric flux through a sphere of radius '4a4a' having center at origin is:

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Answer: (d)

  1. 5Q5Q at distance 3a<4a3a < 4a is inside; −2Q-2Q at distance 5a>4a5a > 4a is outside.
  2. ϕ=qencε0=5Qε0\phi = \dfrac{q_{enc}}{\varepsilon_0} = \dfrac{5Q}{\varepsilon_0}
  3. So the answer is (d).
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