Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Field & Field Lines›Question 11

JEE Main 2024 (31 Jan, Shift 1) · Electric Field & Field Lines

Electric Field & Field Lines question from JEE Main 2024 (31 Jan, Shift 1)

Q11JEE Main 2024 · 31 JAN · SHIFT 1Easy

Electric Field & Field Lines

Two charges qq and 3q3q are separated by a distance 'rr' in air. At a distance xx from charge qq, the resultant electric field is zero. The value of xx is:

Show answer and solution

Answer: (c)

  1. For like charges the null point lies between them: kqx2=k(3q)(r−x)2\dfrac{kq}{x^2} = \dfrac{k(3q)}{(r-x)^2}.
  2. r−xx=3⇒x=r1+3\dfrac{r-x}{x} = \sqrt{3} \Rightarrow x = \dfrac{r}{1+\sqrt{3}}
  3. So the answer is (c) r1+3\dfrac{r}{1+\sqrt{3}}.
Report a mistake

More questions on Electric Field & Field Lines