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MHT CET 2026 (16 Apr, Shift 2) · Electrostatic Potential Energy

Electrostatic Potential Energy question from MHT CET 2026 (16 Apr, Shift 2)

Q11MHT CET 2026 · 16 APR · SHIFT 2Medium

Electrostatic Potential Energy

Two charges q1q_1 and q2q_2 are separated by a distance of 30cm. A third charge q3q_3 initially at point C is shown in figure, is moved along the circular path of radius 40 cm from C to D. If the difference in potential energy due to movement of q3q_3 from C to D is q3k/4πε0q_3k/4\pi\varepsilon_0, the value of K is (ε0\varepsilon_0 = permittivity of free space)

Figure

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Answer: (a)

  1. q3q_3 stays 40 cm from q1q_1, so only the q2q_2 term changes.
  2. BC=402+302=50BC = \sqrt{40^2 + 30^2} = 50 cm =0.5= 0.5 m; BD=40−30=10BD = 40 - 30 = 10 cm =0.1= 0.1 m.
  3. ΔU=q2q34πε0(10.1−10.5)=q3(8q2)4πε0\Delta U = \dfrac{q_2q_3}{4\pi\varepsilon_0}\left(\dfrac{1}{0.1} - \dfrac{1}{0.5}\right) = \dfrac{q_3(8q_2)}{4\pi\varepsilon_0}
  4. So k=8q2k = 8q_2, answer (a).
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