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MHT CET 2026 (13 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2026 (13 May, Shift 2)

Q8MHT CET 2026 · 13 MAY · SHIFT 2Medium

Biot-Savart Law & Circular Coils

Two circular coils $A$ and $B$ are made from the same wire but the radius of coil $A$ is twice that of coil $B$ . What is the ratio of potential difference applied across them, so that the magnetic field at their centres is the same?

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Answer: (b)

$B = \frac{\mu_0 I}{2r}$ same at both centres $\Rightarrow I \propto r$ .
Same wire: resistance $\propto$ length $\propto r$ .
$V = IR \propto r \cdot r = r^2 \Rightarrow V_A : V_B = 4 : 1$
So the answer is (b) $4 : 1$ .

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