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MHT CET 2026 (15 May, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2026 (15 May, Shift 1)

Q7MHT CET 2026 · 15 MAY · SHIFT 1Medium

Biot-Savart Law & Circular Coils

Two circular coils A and B are made from same wire but the radius of coil A is twice that of coil B. If the magnetic field at their centres is same then the ratio potential difference applied across them is

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Answer: (b)

  1. Single-turn coils: B=μ0I2rB = \frac{\mu_0 I}{2r}; equal BB needs I∝rI \propto r.
  2. Same wire (same area, same material): Rwire∝length=2πrR_{wire} \propto \text{length} = 2\pi r, so Rwire∝rR_{wire} \propto r.
  3. V=IRwire∝r2⇒VAVB=(21)2=4V = IR_{wire} \propto r^2 \Rightarrow \frac{V_A}{V_B} = \left(\frac{2}{1}\right)^2 = 4
  4. So the answer is (b) 4:14 : 1.
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