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JEE Main 2026 (6 Apr, Shift 1) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from JEE Main 2026 (6 Apr, Shift 1)

Q16JEE Main 2026 · 6 APR · SHIFT 1Difficult

Gas Laws & Ideal Gas Equation

Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure 90 kPa and temperature 400 K. Keeping the temperature of one vessel constant at 400 K the second vessel temperature is raised to 500 K. The final pressure in the vessels is ______ kPa.

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Answer: (a)

  1. Total moles are conserved and the final pressure PP is common: 90V400+90V400=PV400+PV500\frac{90V}{400} + \frac{90V}{400} = \frac{PV}{400} + \frac{PV}{500}.
  2. 0.45=P(0.0025+0.0020)=0.0045P0.45 = P(0.0025 + 0.0020) = 0.0045P.
  3. P=100P = 100 kPa.
  4. So the answer is (a) 100.
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