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JEE Main 2022 (27 Jul, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from JEE Main 2022 (27 Jul, Shift 2)

Q67JEE Main 2022 · 27 JUL · SHIFT 2Medium

Superposition, Coherence & Intensity

Two coherent sources of light interfere. The intensity ratio of two sources is $1 : 4$ . For this interference pattern if the value of $\frac{I_{\max} + I_{\min}}{I_{\max} - I_{\min}}$ is equal to $\frac{2\alpha + 1}{\beta + 3}$ , then $\frac{\alpha}{\beta}$ will be:

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Answer: (b)

$I_1 : I_2 = 1 : 4 \Rightarrow$ amplitudes $1 : 2$ , so $I_{max} = 9$ , $I_{min} = 1$ (units).
$\frac{I_{max}+I_{min}}{I_{max}-I_{min}} = \frac{10}{8} = \frac{5}{4}$
Match $\frac{2\alpha+1}{\beta+3} = \frac{5}{4}$ : $\alpha = 2$ , $\beta = 1$ .
$\frac{\alpha}{\beta} = 2$ . So the answer is (b) 2.

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