Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Reflection, Superposition & Interference›Question 18

JEE Main 2020 (5 Sep, Shift 2) · Reflection, Superposition & Interference

Reflection, Superposition & Interference question from JEE Main 2020 (5 Sep, Shift 2)

Q18JEE Main 2020 · 5 SEP · SHIFT 2Difficult

Reflection, Superposition & Interference

Two coherent sources of sound, S1 and S2, produce sound waves of the same wavelength, λ\lambda = 1 m, in phase. S1 and S2 are placed 1.5 m apart (see fig). A listener, located at L, directly in front of S2 finds that the intensity is at a minimum

when he is 2 m away from S2. The listener moves away from S1, keeping his distance from S2 fixed. The adjacent maximum of intensity is observed when the listener is at a distance d from S1. Then, d is:

Figure

Show answer and solution

Answer: (c)

  1. At LL: S1L=1.52+22=2.5 mS_1L = \sqrt{1.5^2 + 2^2} = 2.5\text{ m}, path difference =2.5−2=0.5 m=λ2= 2.5 - 2 = 0.5\text{ m} = \frac{\lambda}{2} (minimum).
  2. Moving away from S1S_1 increases the path difference; the next maximum needs path difference =λ=1 m= \lambda = 1\text{ m}.
  3. d−2=1⇒d=3 md - 2 = 1 \Rightarrow d = 3\text{ m}.
  4. So the answer is (c) 3 m3\text{ m}.
Report a mistake

More questions on Reflection, Superposition & Interference