Two coils have a mutual inductance 0.003 H. The current changes in the first coil according to equation I = I₀ sin ω t, where I₀ = 8 A and ω = 100π rad s⁻¹. The maximum value of e.m.f. in the second coil is (a) 2π V (b) 2.4π V (c) 5π V (d) 7.2π V

Answer: (b). e = -MdI/dt = -MI₀ωcos ω t, so emax = MI₀ω emax = 0.003 × 8 × 100π = 2.4π V So the answer is (b) 2.4π V.

Two coils have a mutual inductance 0.003 H. The current changes in… | MHT CET 2024 (10 May, Shift 1)

Q25MHT CET 2024 · 10 MAY · SHIFT 1Easy

Mutual Inductance

Two coils have a mutual inductance 0.003 H. The current changes in the first coil according to equation $I = I_0 \sin \omega t$ , where $I_0 = 8\text{ A}$ and $\omega = 100\pi\text{ rad s}^{-1}$ . The maximum value of e.m.f. in the second coil is

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Answer: (b)

$e = -M\dfrac{dI}{dt} = -MI_0\omega\cos\omega t$ , so $e_{max} = MI_0\omega$
$e_{max} = 0.003 \times 8 \times 100\pi = 2.4\pi\text{ V}$
So the answer is (b) $2.4\pi\text{ V}$ .

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Mutual Inductance question from MHT CET 2024 (10 May, Shift 1)

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