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MHT CET 2023 (12 May, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2023 (12 May, Shift 1)

Q36MHT CET 2023 · 12 MAY · SHIFT 1Easy

Mutual Inductance

Two coils have a mutual inductance of 0.004 H0.004\text{ H}. The current changes in the first coil according to equation I=I0sin⁡ωtI = I_0 \sin \omega t, where I0=10 AI_0 = 10\text{ A} and ω=50π rad s−1\omega = 50\pi\text{ rad s}^{-1}. The maximum value of e.m.f. in the second coil in volt is

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Answer: (d)

  1. emax=M(dIdt)max=MI0ωe_{max} = M\left(\dfrac{dI}{dt}\right)_{max} = MI_0\omega
  2. emax=0.004×10×50π=2π Ve_{max} = 0.004 \times 10 \times 50\pi = 2\pi\text{ V}
  3. So the answer is (d) 2π2\pi.
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