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MHT CET 2026 (18 Apr, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2026 (18 Apr, Shift 1)

Q4MHT CET 2026 · 18 APR · SHIFT 1Easy

Mutual Inductance

Two coils have a mutual inductance of 0.0050.005 H. The current changes in the first coil according to equation I=I0sin⁡ωtI = I_0 \sin \omega t, where I0=10I_0 = 10 A and ω=60π\omega = 60\pi rad s−1{}^{-1}. The maximum values of e.m.f. in the second coil in volt will be

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Answer: (b)

  1. emax⁡=MI0ωe_{\max} = M I_0 \omega
  2. emax⁡=0.005×10×60π=3πe_{\max} = 0.005 \times 10 \times 60\pi = 3\pi V
  3. So the answer is (b) 3π3\pi.
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