Two coils have a mutual inductance of 0.005 H. The current changes in the first coil according to equation I = I₀ sin ω t, where I₀ = 10 A and ω = 100π rad/s. The maximum value of emf in the second coil is (a) 2π (b) 5π (c) π (d) 4π

Answer: (b). emax = MI₀ω emax = 0.005 × 10 × 100π = 5π V So the answer is (b) 5π.

Two coils have a mutual inductance of 0.005 H. The current changes in… | NEET 1998 (AIPMT)

Q64NEET 1998 · AIPMTEasy

Mutual Inductance

Two coils have a mutual inductance of $0.005\text{ H}$ . The current changes in the first coil according to equation $I = I_0 \sin \omega t$ , where $I_0 = 10\text{ A}$ and $\omega = 100\pi\text{ rad/s}$ . The maximum value of emf in the second coil is

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Answer: (b)

$e_{max} = MI_0\omega$
$e_{max} = 0.005 \times 10 \times 100\pi = 5\pi\text{ V}$
So the answer is (b) $5\pi$ .

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Mutual Inductance question from NEET 1998 (AIPMT)

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