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MHT CET 2019 (2 May, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2019 (2 May, Shift 1)

Q54MHT CET 2019 · 2 MAY · SHIFT 1Easy

Mutual Inductance

Two coils have a mutual inductance of 0.01 H. The current in the first coil changes according to equation, I=5sin⁡200πtI = 5\sin 200\pi t. The maximum value of emf induced in the second coil is

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Answer: (a)

  1. emax=MI0ωe_{max} = MI_0\omega with I0=5 AI_0 = 5\text{ A}, ω=200π rad/s\omega = 200\pi\text{ rad/s}
  2. emax=0.01×5×200π=10π Ve_{max} = 0.01 \times 5 \times 200\pi = 10\pi\text{ V}
  3. So the answer is (a) 10π V10\pi\text{ V}.
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