Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i = i₀ sin ω t, where i₀ = 5 A and ω = 50π rad/s. The maximum value of emf in the second coil is (π)/(α) V. The value of α is _______. Numerical answer type. Work it out, then open the answer.

Answer: 2. emax = Mi₀ω = 0.002 × 5 × 50π = 0.5π V 0.5π = (π)/(α) ⇒ α = 2 So α = 2.

Two coils have mutual inductance 0.002 H. The current changes in the… | JEE Main 2024 (27 Jan, Shift 1)

Q28JEE Main 2024 · 27 JAN · SHIFT 1Easy

Mutual Inductance

Two coils have mutual inductance $0.002\text{ H}$ . The current changes in the first coil according to the relation $i = i_0 \sin \omega t$ , where $i_0 = 5\text{ A}$ and $\omega = 50\pi$ rad/s. The maximum value of emf in the second coil is $\frac{\pi}{\alpha}\text{ V}$ . The value of $\alpha$ is _______.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

$e_{max} = Mi_0\omega = 0.002 \times 5 \times 50\pi = 0.5\pi\text{ V}$
$0.5\pi = \dfrac{\pi}{\alpha} \Rightarrow \alpha = 2$
So $\alpha = 2$ .

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