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MHT CET 2026 (17 Apr, Shift 2) · Mutual Inductance

Mutual Inductance question from MHT CET 2026 (17 Apr, Shift 2)

Q9MHT CET 2026 · 17 APR · SHIFT 2Easy

Mutual Inductance

Two coils having self-inductance L1=75L_1 = 75 mH and L2=48L_2 = 48 mH are coupled with each other. If the mutual inductance of the coils is 37.2 mH, then coefficient of coupling will be

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Answer: (c)

  1. k=ML1L2k = \dfrac{M}{\sqrt{L_1L_2}}
  2. 75×48=3600=60 mH\sqrt{75 \times 48} = \sqrt{3600} = 60\text{ mH}
  3. k=37.260=0.62k = \dfrac{37.2}{60} = 0.62
  4. So the answer is (c) 0.620.62.
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