Two coils P and Q are kept near each other. When no current flows through coil P and current increases in coil Q at the rate of 10 A/s, the e.m.f. in coil P is 15 mV. When coil Q carries no current and current of 1.8 A flows through coil P, the magnetic flux linked with coil Q is (a) 1.8 mWb (b) 2.7 mWb (c) 1.5 mWb (d) 1 mWb

Answer: (b). M = (eP)/(dIQ/dt) = 15× 10⁻³10 = 1.5× 10⁻³ H ΦQ = M IP = 1.5× 10⁻³× 1.8 = 2.7× 10⁻³ Wb So the answer is (b) 2.7 mWb.

Two coils P and Q are kept near each other. When no current flows… | MHT CET 2025 (21 Apr, Shift 1)

Q19MHT CET 2025 · 21 APR · SHIFT 1Easy

Mutual Inductance

Two coils $P$ and $Q$ are kept near each other. When no current flows through coil $P$ and current increases in coil Q at the rate of $10\text{ A/s}$ , the e.m.f. in coil P is 15 mV. When coil Q carries no current and current of 1.8 A flows through coil $P$ , the magnetic flux linked with coil Q is

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Answer: (b)

$M = \dfrac{e_P}{dI_Q/dt} = \dfrac{15\times 10^{-3}}{10} = 1.5\times 10^{-3}$ H
$\Phi_Q = M I_P = 1.5\times 10^{-3}\times 1.8 = 2.7\times 10^{-3}$ Wb
So the answer is (b) 2.7 mWb.

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Mutual Inductance question from MHT CET 2025 (21 Apr, Shift 1)

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