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MHT CET 2023 (13 May, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2023 (13 May, Shift 1)

Q50MHT CET 2023 · 13 MAY · SHIFT 1Easy

Biot-Savart Law & Circular Coils

Two concentric circular coils A and B have radii 20 cm20\text{ cm} and 10 cm10\text{ cm} respectively lie in the same plane. The current in coil A is 0.5 A0.5\text{ A} in anticlockwise direction. The current in coil B so that net field at the common centre is zero, is

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Answer: (c)

  1. For zero net field: IArA=IBrB\frac{I_A}{r_A} = \frac{I_B}{r_B} with opposite directions.
  2. IB=0.5×1020=0.25 AI_B = 0.5\times\frac{10}{20} = 0.25\text{ A}, flowing opposite to A, i.e. clockwise.
  3. So the answer is (c) 0.25 A clockwise.
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