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MHT CET 2024 (15 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2024 (15 May, Shift 2)

Q38MHT CET 2024 · 15 MAY · SHIFT 2Easy

Biot-Savart Law & Circular Coils

Two concentric circular coils A and B having radii 20 cm and 10 cm respectively lie in the same plane. The current in coil A is 0.5 A in anticlockwise direction. The current in coil B, so that net magnetic field at the common centre is zero, is

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Answer: (c)

  1. For zero net field: μ0IA2rA=μ0IB2rB\frac{\mu_0 I_A}{2r_A} = \frac{\mu_0 I_B}{2r_B}, with fields opposite.
  2. IB=IArBrA=0.5×1020=0.25 AI_B = I_A\frac{r_B}{r_A} = 0.5\times\frac{10}{20} = 0.25\text{ A}
  3. Opposite field needs opposite current, i.e. clockwise.
  4. So the answer is (c) 0.25 A clockwise.
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