Physics Circle home Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Biot-Savart Law & Circular Coils›Question 79

MHT CET 2021 (22 Sep, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2021 (22 Sep, Shift 1)

Q79MHT CET 2021 · 22 SEP · SHIFT 1Medium

Biot-Savart Law & Circular Coils

Two concentric coplanar circular loops of radii 'r1r_1' and 'r2r_2 ' respectively carry currents 'i1i_1 ' and 'i2i_2' in opposite directions (one clockwise and other anticlockwise). The magnetic induction at the centre of the loops is half that due to 'i1i_1' alone at the centre. If r2=2r1r_2 = 2r_1, the value of i2i1\frac{i_2}{i_1}

Show answer and solution

Answer: (b)

  1. Opposite currents: B=μ0i12r1−μ0i22r2=12⋅μ0i12r1B = \dfrac{\mu_0 i_1}{2r_1}-\dfrac{\mu_0 i_2}{2r_2} = \dfrac{1}{2}\cdot\dfrac{\mu_0 i_1}{2r_1}
  2. i2r2=i12r1\dfrac{i_2}{r_2} = \dfrac{i_1}{2r_1}; with r2=2r1r_2 = 2r_1: i22r1=i12r1\dfrac{i_2}{2r_1} = \dfrac{i_1}{2r_1}
  3. i2i1=1\dfrac{i_2}{i_1} = 1
  4. So the answer is (b) 1.
Report a mistake

More questions on Biot-Savart Law & Circular Coils