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MHT CET 2026 (12 May, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2026 (12 May, Shift 1)

Q11MHT CET 2026 · 12 MAY · SHIFT 1Easy

Mutual Inductance

Two conducting circular loops of radii $r$ and $2r$ are placed in the same plane with their centres coinciding. The mutual inductance $M$ between them is {same current is passing through both the coils} ( $\mu_0 =$ permeability of free space)

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Answer: (b)

Using the small-inner-loop result $M = \dfrac{\mu_0\pi r_2^2}{2r_1}$ with $r_1 = 2r$ , $r_2 = r$
$M = \dfrac{\mu_0\pi r^2}{2(2r)} = \dfrac{\mu_0\pi r}{4}$
So the answer is (b) $\dfrac{\mu_0\pi r}{4}$ .

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