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MHT CET 2025 (23 Apr, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2025 (23 Apr, Shift 2)

Q30MHT CET 2025 · 23 APR · SHIFT 2Medium

Biot-Savart Law & Circular Coils

Two current carrying identical coils are kept as shown in figure. The magnetic field at centre ' O ' is ( N and R represent the number of turns and radius of each coil respectively, μ0=\mu_0 = permeability of free space)

Figure

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Answer: (b)

  1. Each coil gives B=μ0NI2RB = \dfrac{\mu_0 NI}{2R} at O.
  2. The coils are perpendicular, so the two fields are perpendicular.
  3. Bnet=2⋅μ0NI2R=μ0NI2RB_{net} = \sqrt{2}\cdot\dfrac{\mu_0 NI}{2R} = \dfrac{\mu_0 NI}{\sqrt{2}R}
  4. So the answer is (b).
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