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MHT CET 2025 (26 Apr, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2025 (26 Apr, Shift 2)

Q69MHT CET 2025 · 26 APR · SHIFT 2Medium

Thermodynamic Processes

Two cylinders A and B fitted with piston contain equal amount of an ideal diatomic gas at temperature T K. The piston of cylinder A is free to move while that of cylinder BB is held fixed. The same amount of heat is given to the gas in each cylinder. If the rise of temperature of the gas in A is dTAdT_A, then the rise in temperature of the gas in B is (γ=CpCv)\left(\gamma = \frac{C_p}{C_v}\right)

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Answer: (c)

  1. A is at constant pressure, B at constant volume; same heat: nCp dTA=nCv dTBnC_p\,dT_A = nC_v\,dT_B.
  2. dTB=CpCvdTA=γ dTAdT_B = \dfrac{C_p}{C_v}dT_A = \gamma\,dT_A
  3. So the answer is (c) γ dTA\gamma\,dT_A.
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