Student Login

Home›Chapters›Nuclear Physics PYQs›Nuclear Fission & Fusion›Question 24

JEE Main 2017 (8 Apr, Shift 1) · Nuclear Fission & Fusion

Nuclear Fission & Fusion question from JEE Main 2017 (8 Apr, Shift 1)

Q24JEE Main 2017 · 8 APR · SHIFT 1Easy

Nuclear Fission & Fusion

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is: (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

Show answer and solution

Answer: (c)

$Q = \text{BE}({}^4\text{He}) - 2\,\text{BE}({}^2\text{H}) = 4\times7.0 - 2\times2\times1.1$ .
$Q = 28.0 - 4.4 = 23.6\text{ MeV}$ .
So the answer is (c) $23.6\text{ MeV}$ .

Report a mistake

More questions on Nuclear Fission & Fusion

When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can…JEE Main 2013 (9 Apr, Shift 1)
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect…NEET 2013
Fusion reaction takes place at high temperature becauseNEET 2011 (AIPMT, Prelims)
The power obtained in a reactor using U235 disintegration is 1000 kW. The mass decay of…NEET 2011 (AIPMT, Prelims)
The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV…NEET 2010 (AIPMT, Mains)
The binding energy of deuteron is 2.2 MeV and that of ⁴₂ He is 28 MeV. If two deuterons…NEET 2006 (AIPMT)
In any fission process the ratio mass of fission products is mass of parent nucleusNEET 2005 (AIPMT)
Fission of nuclei is possible because the binding energy per nucleon in themNEET 2005 (AIPMT)