Two different coils have self-inductance 3L and L. The current in… | MHT CET 2026 (19 Apr, Shift 1)

Q18MHT CET 2026 · 19 APR · SHIFT 1Medium

Self-Inductance & Energy

Two different coils have self-inductance $3L$ and $L$ . The current in both the coils is increased at the same constant rate. At certain instant of time, the power given to the two coils is same. At that time there was current and voltage induced in the two coils. At the same instant, the ratio of energy stored in the first coil to that in the second coil is

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Answer: (b)

Power to a coil $P = e I = L I \dfrac{dI}{dt}$ ; same $P$ and same $\dfrac{dI}{dt}$ give $L_1 I_1 = L_2 I_2$ .
$3L\, I_1 = L\, I_2 \Rightarrow \dfrac{I_1}{I_2} = \dfrac{1}{3}$
$\dfrac{U_1}{U_2} = \dfrac{\tfrac12 (L_1 I_1) I_1}{\tfrac12 (L_2 I_2) I_2} = \dfrac{I_1}{I_2} = \dfrac{1}{3}$
So the answer is (b) $1 : 3$ .

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