Physics Circle home Student Login

Home›Chapters›Nuclear Physics PYQs›Law of Radioactive Decay›Question 5

MHT CET 2026 (15 Apr, Shift 1) · Law of Radioactive Decay

Law of Radioactive Decay question from MHT CET 2026 (15 Apr, Shift 1)

Q5MHT CET 2026 · 15 APR · SHIFT 1Easy

Law of Radioactive Decay

Two different radioactive elements with half lives T1T_1 and T2T_2 have undecayed atoms N1N_1 and N2N_2 respectively, present at a given instant. The ratio of their activities at this instant is

Show answer and solution

Answer: (b)

  1. Activity A=λN=0.693TNA = \lambda N = \frac{0.693}{T}N.
  2. A1A2=N1/T1N2/T2=N1T2N2T1\frac{A_1}{A_2} = \frac{N_1/T_1}{N_2/T_2} = \frac{N_1T_2}{N_2T_1}.
  3. So the answer is (b) N1T2N2T1\frac{N_1T_2}{N_2T_1}.
Report a mistake

More questions on Law of Radioactive Decay