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JEE Main 2019 (12 Jan, Shift 1) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from JEE Main 2019 (12 Jan, Shift 1)

Q44JEE Main 2019 · 12 JAN · SHIFT 1Medium

Electrical Power & Heating Effect

Two electric bulbs, rated at (25 W, 220 V) and (100 W, 220 V), are connected in series across a 220 V voltage source. If the 25 W and 100 W bulbs draw powers P1 and P2 respectively, then:

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Answer: (b)

  1. R1=220225=1936 ΩR_1 = \frac{220^2}{25} = 1936\ \Omega, R2=2202100=484 ΩR_2 = \frac{220^2}{100} = 484\ \Omega.
  2. Series current I=2201936+484=111I = \frac{220}{1936 + 484} = \frac{1}{11} A.
  3. P1=I2R1=1936121=16P_1 = I^2R_1 = \frac{1936}{121} = 16 W, P2=484121=4P_2 = \frac{484}{121} = 4 W.
  4. So the answer is (b) P1=16P_1 = 16 W, P2=4P_2 = 4 W.
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