Two electric dipoles of dipole moments 1.2 × 10⁻³⁰ Cm and 2.4 × 10⁻³⁰ Cm are placed in two different uniform electric fields of strengths 5 × 10⁴ NC⁻¹ and 15 × 10⁴ NC⁻¹ respectively. The ratio of maximum torque experienced by the electric dipoles will be 1/x. The value of x is __________. Numerical answer type. Work it out, then open the answer.

Answer: 6. τmax = pE, so (τ₁)/(τ₂) = (p₁E₁)/(p₂E₂) (τ₁)/(τ₂) = 1.2×10⁻³⁰ × 5×10⁴2.4×10⁻³⁰ × 15×10⁴ = 6/36 = 1/6 Answer: x = 6

Two electric dipoles of dipole moments 1.2 × 10⁻³⁰ Cm and 2.4 × 10⁻³⁰… | JEE Main 2022 (28 Jul, Shift 1)

Q50JEE Main 2022 · 28 JUL · SHIFT 1Easy

Electric Dipole

Two electric dipoles of dipole moments $1.2 \times 10^{-30}\text{ Cm}$ and $2.4 \times 10^{-30}\text{ Cm}$ are placed in two different uniform electric fields of strengths $5 \times 10^{4}\text{ NC}^{-1}$ and $15 \times 10^{4}\text{ NC}^{-1}$ respectively. The ratio of maximum torque experienced by the electric dipoles will be $\frac{1}{x}$ . The value of $x$ is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

$\tau_{max} = pE$ , so $\frac{\tau_1}{\tau_2} = \frac{p_1E_1}{p_2E_2}$
$\frac{\tau_1}{\tau_2} = \frac{1.2\times10^{-30} \times 5\times10^{4}}{2.4\times10^{-30} \times 15\times10^{4}} = \frac{6}{36} = \frac{1}{6}$
Answer: $x = 6$

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Electric Dipole question from JEE Main 2022 (28 Jul, Shift 1)

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