Two electric dipoles of moment P and 8P are placed in opposite directions on a line at a distance of 24 cm. The electric field will be zero at the point between the dipoles whose distance from the dipole of moment P will be x₁. When 8P is replaced by 27P keeping all other quantities the same, the distance x₁ now becomes x₂. The difference |x₂ - x₁| is ( All the distances are measured from the centers of the dipole.) (a) 2 cm (b) 4 cm (c) 6 cm (d) 8 cm

Answer: (a). Point between the dipoles is on both axes; the two axial fields are opposite because the dipoles are opposite. Zero field: (2kP)/(x³) = (2k(nP))/((24 - x)³) ⇒ 24 - x = √[3]n x n = 8: 24 - x₁ = 2x₁ ⇒ x₁ = 8 cm n = 27: 24 - x₂ = 3x₂ ⇒ x₂ = 6 cm |x₂ - x₁| = 2 cm, so the answer is (a).

Two electric dipoles of moment P and 8P are placed in opposite… | MHT CET 2026 (19 Apr, Shift 1)

Q12MHT CET 2026 · 19 APR · SHIFT 1Medium

Electric Dipole

Two electric dipoles of moment $P$ and $8P$ are placed in opposite directions on a line at a distance of $24$ cm. The electric field will be zero at the point between the dipoles whose distance from the dipole of moment $P$ will be $x_1$ . When $8P$ is replaced by $27P$ keeping all other quantities the same, the distance $x_1$ now becomes $x_2$ . The difference $|x_2 - x_1|$ is ( All the distances are measured from the centers of the dipole.)

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Answer: (a)

Point between the dipoles is on both axes; the two axial fields are opposite because the dipoles are opposite.
Zero field: $\frac{2kP}{x^3} = \frac{2k(nP)}{(24 - x)^3} \Rightarrow 24 - x = \sqrt[3]{n}\,x$
$n = 8$ : $24 - x_1 = 2x_1 \Rightarrow x_1 = 8$ cm
$n = 27$ : $24 - x_2 = 3x_2 \Rightarrow x_2 = 6$ cm
$|x_2 - x_1| = 2$ cm, so the answer is (a).

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Electric Dipole question from MHT CET 2026 (19 Apr, Shift 1)

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