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MHT CET 2026 (18 Apr, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from MHT CET 2026 (18 Apr, Shift 2)

Q4MHT CET 2026 · 18 APR · SHIFT 2Easy

Electric Charge & Coulomb's Law

Two equal point charges exert a force F on each other when they are placed distance 'd' apart in air. When they are placed distance 'D' apart in a medium of dielectric constant K, they exert the same force. The distance D is equal to

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Answer: (a)

$\dfrac{kq^2}{d^2} = \dfrac{kq^2}{K D^2}$
$D^2 = \dfrac{d^2}{K} \Rightarrow D = \dfrac{d}{\sqrt{K}}$
So the answer is (a) $\dfrac{d}{\sqrt{K}}$ .

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