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MHT CET 2025 (19 Apr, Shift 2) · Pressure & Kinetic Energy of a Gas

Pressure & Kinetic Energy of a Gas question from MHT CET 2025 (19 Apr, Shift 2)

Q10MHT CET 2025 · 19 APR · SHIFT 2Easy

Pressure & Kinetic Energy of a Gas

Two gases A and B are at absolute temperatures 350 K and 420 K respectively. The ratio of average kinetic energy of the molecules of gas BB to that of gas A is

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Answer: (a)

  1. Average KE =32kBT= \frac{3}{2}k_BT, so EBEA=TBTA\frac{E_B}{E_A} = \frac{T_B}{T_A}.
  2. 420350=65\frac{420}{350} = \frac{6}{5}
  3. So the answer is (a) 6:56:5.
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