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MHT CET 2024 (11 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2024 (11 May, Shift 1)

Q123MHT CET 2024 · 11 MAY · SHIFT 1Medium

Thermodynamic Processes

Two gases A and B having same initial state ( P,V,n,TP, V, n, T ). Now gas A is compressed to V8\frac{V}{8} by isothermal process and other gas B is compressed to V8\frac{V}{8} by adiabatic process. The ratio of final pressure of gas AA and BB is (Both gases are monoatomic, γ=5/3\gamma = 5/3)

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Answer: (b)

  1. Isothermal: PA=P×8=8PP_A = P \times 8 = 8P.
  2. Adiabatic: PB=P×85/3=32PP_B = P \times 8^{5/3} = 32P.
  3. PAPB=832=14\frac{P_A}{P_B} = \frac{8}{32} = \frac{1}{4}
  4. So the answer is (b) 14\frac{1}{4}.
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