Two identical capacitors C₁ and C₂ of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor C₁ using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy? (a) 25% (b) 75% (c) 0% (d) 50%

Answer: (d). Ui = 1/2CV²; after sharing with an equal capacitor, V' = V/2. Uf = 1/2(2C)(V/2)² = 1/4CV² = Ui/2 Loss = 50%, so the answer is (d).

Two identical capacitors C₁ and C₂ of equal capacitance are connected… | NEET 2019

Q30NEET 2019Medium

Charge Sharing & Loss of Energy

Two identical capacitors $C_1$ and $C_2$ of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor $C_1$ using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy?

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Answer: (d)

$U_i = \frac{1}{2}CV^2$ ; after sharing with an equal capacitor, $V' = \frac{V}{2}$ .
$U_f = \frac{1}{2}(2C)\left(\frac{V}{2}\right)^2 = \frac{1}{4}CV^2 = \frac{U_i}{2}$
Loss $= 50\%$ , so the answer is (d).

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