Physics Circle home Student Login

Home›Chapters›Capacitors PYQs›Charge Sharing & Loss of Energy›Question 24

MHT CET 2021 (24 Sep, Shift 1) · Charge Sharing & Loss of Energy

Charge Sharing & Loss of Energy question from MHT CET 2021 (24 Sep, Shift 1)

Q24MHT CET 2021 · 24 SEP · SHIFT 1Medium

Charge Sharing & Loss of Energy

Two identical capacitors have the same capacitance 'CC'. One of them is charged to potential 'V1V_1' and the other to V2V_2. The negative ends of the capacitors are connected together. When positive ends are also connected, the decrease in energy of the combined system is

Show answer and solution

Answer: (a)

  1. Loss on joining like plates: ΔU=12C1C2C1+C2(V1−V2)2\Delta U = \frac{1}{2}\frac{C_1C_2}{C_1 + C_2}(V_1 - V_2)^2
  2. With equal CC: C1C2C1+C2=C2\frac{C_1C_2}{C_1 + C_2} = \frac{C}{2}
  3. ΔU=14C(V1−V2)2\Delta U = \frac{1}{4}C(V_1 - V_2)^2, so the answer is (a).
Report a mistake

More questions on Charge Sharing & Loss of Energy