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MHT CET 2024 (9 May, Shift 2) · Terminal Velocity

Terminal Velocity question from MHT CET 2024 (9 May, Shift 2)

Q21MHT CET 2024 · 9 MAY · SHIFT 2Easy

Terminal Velocity

Two identical drops of water are falling through air with steady velocity ' V '. If the two drops come together to form a single drop. The new velocity of the single drop is

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Answer: (c)

  1. Volume is conserved: 43πR3=2⋅43πr3⇒R=21/3r\frac{4}{3}\pi R^3 = 2\cdot\frac{4}{3}\pi r^3 \Rightarrow R = 2^{1/3}r.
  2. Terminal velocity v∝r2v \propto r^2.
  3. V′=V(21/3)2=22/3VV' = V\left(2^{1/3}\right)^2 = 2^{2/3}V
  4. So the answer is (c) (2)2/3V(2)^{2/3}V.
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