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MHT CET 2025 (21 Apr, Shift 1) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2025 (21 Apr, Shift 1)

Q17MHT CET 2025 · 21 APR · SHIFT 1Medium

Magnetic Field of Straight Wires

Two identical long parallel wires carry currents ' I1I_1 ' and ' I2I_2 ' such that I1>I2I_1 > I_2. When the currents are in the same direction, the magnetic field at a point midway between the wires is 8×10−6 T8 \times 10^{-6}\text{ T}. If the direction of I2I_2 is reversed, the field becomes 3.2×10−5 T3.2 \times 10^{-5}\text{ T}. The ratio of I2I_2 to I1I_1 is

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Answer: (c)

  1. Same direction: k(I1−I2)=8×10−6k(I_1 - I_2) = 8 \times 10^{-6}; reversed: k(I1+I2)=3.2×10−5k(I_1 + I_2) = 3.2 \times 10^{-5}.
  2. I1+I2I1−I2=4⇒3I1=5I2\frac{I_1 + I_2}{I_1 - I_2} = 4 \Rightarrow 3I_1 = 5I_2
  3. I2:I1=3:5I_2 : I_1 = 3 : 5
  4. So the answer is (c) 3:53 : 5.
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