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JEE Main 2022 (29 Jul, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2022 (29 Jul, Shift 2)

Q46JEE Main 2022 · 29 JUL · SHIFT 2Medium

Electric Charge & Coulomb's Law

Two identical metallic spheres AA and BB when placed at certain distance in air repel each other with a force of FF. Another identical uncharged sphere CC is first placed in contact with AA and then in contact with BB and finally placed at midpoint between spheres A and B. The force experienced by sphere C will be:

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Answer: (b)

  1. Let each charge be qq, F=kq2r2F = \dfrac{kq^2}{r^2}. After contacts: A=q2A = \dfrac{q}{2}, B=C=3q4B = C = \dfrac{3q}{4}.
  2. C at midpoint, distance r/2r/2 from each. Force from A on C =k(q/2)(3q/4)r2/4=32F= \dfrac{k(q/2)(3q/4)}{r^2/4} = \dfrac{3}{2}F (towards B).
  3. Force from B on C =k(3q/4)2r2/4=94F= \dfrac{k(3q/4)^2}{r^2/4} = \dfrac{9}{4}F (towards A).
  4. Net =94F−32F=34F= \dfrac{9}{4}F - \dfrac{3}{2}F = \dfrac{3}{4}F. So the answer is (b) 3F/43F/4.
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