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MHT CET 2026 (13 Apr, Shift 1) · Dielectrics

Dielectrics question from MHT CET 2026 (13 Apr, Shift 1)

Q23MHT CET 2026 · 13 APR · SHIFT 1Medium

Dielectrics

Two identical parallel plate air capacitors are connected in series to a battery of e.m.f. 'V'. If one of the capacitor is inserted in liquid of dielectric constant 'K' then potential difference of the other capacitor will become

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Answer: (a)

In series the charge is the same, so $V \propto \frac{1}{C}$ .
Capacitances become $KC$ and $C$ ; the unfilled one ( $C$ ) takes the larger share.
$V_{other} = V \cdot \frac{KC}{KC + C} = \frac{KV}{K+1}$
So the answer is (a) $\frac{KV}{K+1}$ .

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