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JEE Main 2023 (15 Apr, Shift 1) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2023 (15 Apr, Shift 1)

Q37JEE Main 2023 · 15 APR · SHIFT 1Medium

Satellites - Orbital Velocity & Period

Two identical particles each of mass ' mm ' go round a circle of radius aa under the action of their mutual gravitational attraction. The angular speed of each particle will be:

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Answer: (d)

  1. Separation is 2a2a: Gm2(2a)2=mω2a\frac{Gm^2}{(2a)^2} = m\omega^2 a
  2. ω2=Gm4a3\omega^2 = \frac{Gm}{4a^3}
  3. So the answer is (d) Gm4a3\sqrt{\frac{Gm}{4a^3}}.
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