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MHT CET 2023 (12 May, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2023 (12 May, Shift 1)

Q61MHT CET 2023 · 12 MAY · SHIFT 1Medium

Self-Inductance & Energy

Two inductors of 60 mH60\text{ mH} each are joined in parallel. The current passing through this combination is 2.2 A2.2\text{ A}. The energy stored in this combination of inductors in joule is

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Answer: (c)

  1. Parallel: Lp=602=30L_p = \dfrac{60}{2} = 30 mH.
  2. U=12×0.03×(2.2)2=0.015×4.84=0.0726U = \dfrac{1}{2}\times 0.03 \times (2.2)^2 = 0.015 \times 4.84 = 0.0726 J
  3. So the answer is (c) 0.0726.
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