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MHT CET 2026 (11 Apr, Shift 1) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from MHT CET 2026 (11 Apr, Shift 1)

Q5MHT CET 2026 · 11 APR · SHIFT 1Easy

Superposition, Coherence & Intensity

Two light waves amplitudes in the ratio $3 : 1$ produce interference. The ratio of the maximum to minimum intensity is

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Answer: (d)

$\frac{I_{max}}{I_{min}} = \left(\frac{a_1+a_2}{a_1-a_2}\right)^2$
$= \left(\frac{3+1}{3-1}\right)^2 = 2^2 = 4$
So the answer is (d) $4 : 1$ .

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