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JEE Main 2020 (3 Sep, Shift 2) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from JEE Main 2020 (3 Sep, Shift 2)

Q56JEE Main 2020 · 3 SEP · SHIFT 2Medium

YDSE: Film, Medium & Two Wavelengths

Two light waves having the same wavelength $\lambda$ in vacuum are in phase initially. Then the first wave travels a path L1 through a medium of refractive index n1 while the second wave travels a path of length L2 through a medium of refractive index n2. After this the phase difference between the two waves is:

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Answer: (a)

Optical paths: $n_1 L_1$ and $n_2 L_2$ .
Phase difference $= \frac{2\pi}{\lambda}(n_1L_1 - n_2L_2)$
So the answer is (a).

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