Two long conductors, separated by a distance ' d ' carry currents '… | MHT CET 2021 (24 Sep, Shift 1)

Q44MHT CET 2021 · 24 SEP · SHIFT 1Medium

Force on Current-Carrying Conductors

Two long conductors, separated by a distance ' $d$ ' carry currents ' $I_1$ ' and ' $I_2$ ' in the same directions. They exert a force ' $F$ ' on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance is also increased to ' $3d$ '. The new value of the force between them is

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Answer: (c)

$F \propto \frac{I_1 I_2}{d}$
New: $I_2 \to -2I_2$ , $d \to 3d$
$F' = F\times\frac{-2}{3} = -\frac{2F}{3}$ (now repulsive)
So the answer is (c) $-\frac{2F}{3}$ .

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Force on Current-Carrying Conductors question from MHT CET 2021 (24 Sep, Shift 1)

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