Two long conductors separated by a distance ' d ' carry currents I₁… | MHT CET 2023 (11 May, Shift 2)

Q34MHT CET 2023 · 11 MAY · SHIFT 2Medium

Force on Current-Carrying Conductors

Two long conductors separated by a distance ' $d$ ' carry currents $I_1$ and $I_2$ in the same direction. They exert a force ' $F$ ' on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance between them is also increased to $3d$ . The new value of force between them is

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Answer: (c)

$F \propto \frac{I_1 I_2}{d}$
New: $I_2 \to -2I_2$ , $d \to 3d$
$F' = F\times\frac{-2}{3} = -\frac{2F}{3}$ (now repulsive)
So the answer is (c) $\frac{-2F}{3}$ .

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Force on Current-Carrying Conductors question from MHT CET 2023 (11 May, Shift 2)

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